4x^2=33x=29

Solution for 4x^2=33x=29 equation:

4x^2=33x=29

We move all terms to the left:

4x^2-(33x)=0

a = 4; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·4·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*4}=\frac{66}{8}
=8+1/4
$